I have a spare fully populated Adafruit Xbee adapter board but I am faced with the problem in that I want to use it in a setup that can only supply 3V3. What I am wanting to know is if I can just use the parallel pins alongside the buffer chip and supply the 3V3 via VCC. Now, the buffer chip is *there*. I should probably remove it, I assume? Any possibility the radio will work with the buffer chip still there but not being powered? I would guess probably not but just asking in case.
Yes, I basically just need it for converting the pins on the Xbee to something breadboard-friendly in this instance.
I presume the LEDs will no longer work?
Thanks!
edit: kept calling the buffer chip a TTL chip for some reason.
the parallel pins on the breakout
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Re: the parallel pins on the breakout
It should just work as is if you provide 3.3v to the 3.3v pin. The only device on the board connected to +5v is the 3.3v regulator.
http://www.ladyada.net/images/xbee/xbee11sch.png
http://www.ladyada.net/images/xbee/xbee11sch.png
Please be positive and constructive with your questions and comments.