This is my first post ever. I have arrived here at these forums because I have a fantastic idea, but I am only a civil engineer, which means I know jack about building electronics. So I need help. I've searched the forum for something similar but didn't find anything.
I plan to take the "guts" out of the back of a Palm Pre, which consists of an inductive-charging coil and circuit board:http://www.amazon.com/Palm-Pre-Touchsto ... B002UNKGMC
attach it (along with the magnets, for securing the phone to the charger) to the underside of an iPhone case, such as a rubber Otterbox, and charge my iPhone wirelessly on a Palm Touchstone!http://www.amazon.com/Palm-Touchstone-C ... cps_text_b
Something similar has been done with an Evo 4G here:http://www.goodandevo.net/2010/06/how-t ... arger.html
However, as I have learned by reading the MintyBoost project pages, the iPhone has a much more complicated charging schema than the Evo, so I feel a little bit daunted here.
Here is what I know: when charging, the Palm inductive-charging coil delivers about 5V @ 1A across two leads that connect directly to the phone battery (though it may be 5.45V- I need to get out my multimeter and make sure). Since the inductive charger delivers 1A, I am assuming that it will be able to charge an iPhone in the "quick charge" mode at 1A instead of the slower 500mA.
Now we come to the part that I have no idea how to do: I need to take the 5V, 1A delivered by the inductive charging coil and convert it to the three 5V, 2V, and 2.8V lines required by the iPhone USB charger. This is something I am at a loss as to how to do! I have been trying to read up on it, but I am very confused. I wonder if someone could give me some direction? Remember that I have had university physics- which means I have a vague idea of how electricity works, and I am aware of Ohm's law and all of that, but I don't really know a diode from a capacitor. I would like to know how it works, but more importantly is to just know what components I need to buy and how to put them together. I will learn as I build.
Thanks in advance for any help.