OK, so I don't like LadyAda's industrial design. Not so much the enclosure or the tube, which I think are super-sassy, but the button placement. And it's really a simple complaint:
There's no snooze button on the top.
There's no snooze button on the top!
It's an alarm clock, and I don't care what anybody else says, if you can't whack the snooze button whilst half-asleep, if you have to fumble around and find the right button, it's not a good alarm clock. If I wanted an alarm clock that was a pain in the ass to snooze with, well hell: I'd just go buy a clocky
. Actually, I DID buy a clocky. But now I want an Ice Tube, and I want it to work the way I want it to. And since this is an open source product, I should just put my money where my mouth is and modify the thing myself. So, this brings us to my question:
I'd like to put a capacitive touch sensor on the inside of the top face of the Ice Tube Enclosure. I figure if I just go grab something like this
, wire it into a transistor in parallel with the snooze button on the alarm, and yoink, I've got a touch-sensitive snooze button.
My question is, does anybody know if the high voltage inside the case of the Ice Tube likely to increase the noise in the signal, to the point that I'll be unable to sense a finger (or hand) press? There's quite a high voltage being pushed into those VFD segments, and I figure it's possible it's pushing out it's own electric field into the sensor since it's oscillating on and off, (a changing current induces a changing magnetic field induces a changing electric field...)
Can anyone suggest a reason why I'm wrong? Or can anyone give some insight on how noise-sensitive these capacitive touch sensors are? I remember reading LadyAda once saying you couldn't really slave the Ice Tube to an atomic radio signal because of the noise in the enclosure. This seems like it might have the same problem.